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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
916797111901-1
7971196831-17
11983136-17-8
83362117-823
361133-823-77
1133223-77254
3211-77254-331
2120254-331916
So our multiplicative inverse is -331 mod 916 ≡ 585
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
3796180379010
6183791239101
379239114001-1
2391401991-12
14099141-12-3
99412172-38
411727-38-19
177238-1946
7321-1946-111
313046-111379
So our multiplicative inverse is -111 mod 379 ≡ 268
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
365894901-4
899981-437
9811-437-41
818037-41365
So our multiplicative inverse is -41 mod 365 ≡ 324
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 993 × 797-1 (mod 916) ≡ 993 × 585 (mod 916) ≡ 161 (mod 916)
x ≡ 808 × 618-1 (mod 379) ≡ 808 × 268 (mod 379) ≡ 135 (mod 379)
x ≡ 623 × 89-1 (mod 365) ≡ 623 × 324 (mod 365) ≡ 7 (mod 365)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 916 × 379 × 365 = 126714860
  2. We calculate the numbers M1 to M3
    M1=M/m1=126714860/916=138335,   M2=M/m2=126714860/379=334340,   M3=M/m3=126714860/365=347164
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    9161383350916010
    13833591615119101
    9161948401-48
    194431-48193
    4311-48193-241
    3130193-241916
    So our multiplicative inverse is -241 mod 916 ≡ 675
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    3793343400379010
    33434037988262101
    379626701-6
    627861-649
    7611-649-55
    616049-55379
    So our multiplicative inverse is -55 mod 379 ≡ 324
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    3653471640365010
    34716436595149101
    3654972201-7
    4922251-715
    22542-715-67
    522115-67149
    2120-67149-365
    So our multiplicative inverse is 149 mod 365 ≡ 149
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (161 × 138335 × 675 +
       135 × 334340 × 324 +
       7 × 347164 × 149)   mod 126714860
    = 114972817 (mod 126714860)


    So our answer is 114972817 (mod 126714860).


Verification

So we found that x ≡ 114972817
If this is correct, then the following statements (i.e. the original equations) are true:
797x (mod 916) ≡ 993 (mod 916)
618x (mod 379) ≡ 808 (mod 379)
89x (mod 365) ≡ 623 (mod 365)

Let's see whether that's indeed the case if we use x ≡ 114972817.