Bootstrap
  C.R.T. .com
It doesn't have to be difficult if someone just explains it right.

Welcome to ChineseRemainderTheorem.com!

×

Modal Header

Some text in the Modal Body

Some other text...

Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
13911912001-1
119205191-16
201911-16-7
1911906-7139
So our multiplicative inverse is -7 mod 139 ≡ 132
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
3736910373010
6913731318101
37331815501-1
318555431-16
5543112-16-7
4312376-727
12715-727-34
751227-3461
5221-3461-156
212061-156373
So our multiplicative inverse is -156 mod 373 ≡ 217
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
995841115401-1
8411545711-16
15471212-16-13
71125116-1371
121111-1371-84
11111071-84995
So our multiplicative inverse is -84 mod 995 ≡ 911
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 542 × 119-1 (mod 139) ≡ 542 × 132 (mod 139) ≡ 98 (mod 139)
x ≡ 808 × 691-1 (mod 373) ≡ 808 × 217 (mod 373) ≡ 26 (mod 373)
x ≡ 112 × 841-1 (mod 995) ≡ 112 × 911 (mod 995) ≡ 542 (mod 995)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 139 × 373 × 995 = 51587765
  2. We calculate the numbers M1 to M3
    M1=M/m1=51587765/139=371135,   M2=M/m2=51587765/373=138305,   M3=M/m3=51587765/995=51847
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    1393711350139010
    37113513926705101
    139527401-27
    54111-2728
    4140-2728-139
    So our multiplicative inverse is 28 mod 139 ≡ 28
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    3731383050373010
    138305373370295101
    37329517801-1
    295783611-14
    7861117-14-5
    61173104-519
    171017-519-24
    1071319-2443
    7321-2443-110
    313043-110373
    So our multiplicative inverse is -110 mod 373 ≡ 263
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    995518470995010
    5184799552107101
    99510793201-9
    107323111-928
    3211210-928-65
    11101128-6593
    101100-6593-995
    So our multiplicative inverse is 93 mod 995 ≡ 93
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (98 × 371135 × 28 +
       26 × 138305 × 263 +
       542 × 51847 × 93)   mod 51587765
    = 37800592 (mod 51587765)


    So our answer is 37800592 (mod 51587765).


Verification

So we found that x ≡ 37800592
If this is correct, then the following statements (i.e. the original equations) are true:
119x (mod 139) ≡ 542 (mod 139)
691x (mod 373) ≡ 808 (mod 373)
841x (mod 995) ≡ 112 (mod 995)

Let's see whether that's indeed the case if we use x ≡ 37800592.