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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
7857821301-1
782326021-1261
3211-1261-262
2120261-262785
So our multiplicative inverse is -262 mod 785 ≡ 523
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
6778860677010
8866771209101
67720935001-3
20950491-313
50955-313-68
951413-6881
5411-6881-149
414081-149677
So our multiplicative inverse is -149 mod 677 ≡ 528
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
4596250459010
6254591166101
459166212701-2
1661271391-23
12739310-23-11
3910393-1136
10911-1136-47
919036-47459
So our multiplicative inverse is -47 mod 459 ≡ 412
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 196 × 782-1 (mod 785) ≡ 196 × 523 (mod 785) ≡ 458 (mod 785)
x ≡ 745 × 886-1 (mod 677) ≡ 745 × 528 (mod 677) ≡ 23 (mod 677)
x ≡ 966 × 625-1 (mod 459) ≡ 966 × 412 (mod 459) ≡ 39 (mod 459)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 785 × 677 × 459 = 243933255
  2. We calculate the numbers M1 to M3
    M1=M/m1=243933255/785=310743,   M2=M/m2=243933255/677=360315,   M3=M/m3=243933255/459=531445
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    7853107430785010
    310743785395668101
    785668111701-1
    6681175831-16
    11783134-16-7
    83342156-720
    341524-720-47
    1543320-47161
    4311-47161-208
    3130161-208785
    So our multiplicative inverse is -208 mod 785 ≡ 577
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    6773603150677010
    360315677532151101
    67715147301-4
    15173251-49
    735143-49-130
    53129-130139
    3211-130139-269
    2120139-269677
    So our multiplicative inverse is -269 mod 677 ≡ 408
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    4595314450459010
    5314454591157382101
    45938217701-1
    382774741-15
    777413-15-6
    7432425-6149
    3211-6149-155
    2120149-155459
    So our multiplicative inverse is -155 mod 459 ≡ 304
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (458 × 310743 × 577 +
       23 × 360315 × 408 +
       39 × 531445 × 304)   mod 243933255
    = 81913638 (mod 243933255)


    So our answer is 81913638 (mod 243933255).


Verification

So we found that x ≡ 81913638
If this is correct, then the following statements (i.e. the original equations) are true:
782x (mod 785) ≡ 196 (mod 785)
886x (mod 677) ≡ 745 (mod 677)
625x (mod 459) ≡ 966 (mod 459)

Let's see whether that's indeed the case if we use x ≡ 81913638.