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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
698551114701-1
55114731101-14
147110137-14-5
110372364-514
373611-514-19
36136014-19698
So our multiplicative inverse is -19 mod 698 ≡ 679
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
954914601-1
4946131-12
463151-12-31
31302-3195
So our multiplicative inverse is -31 mod 95 ≡ 64
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
5179470517010
9475171430101
51743018701-1
430874821-15
878215-15-6
8251625-6101
5221-6101-208
2120101-208517
So our multiplicative inverse is -208 mod 517 ≡ 309
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 961 × 551-1 (mod 698) ≡ 961 × 679 (mod 698) ≡ 587 (mod 698)
x ≡ 391 × 49-1 (mod 95) ≡ 391 × 64 (mod 95) ≡ 39 (mod 95)
x ≡ 995 × 947-1 (mod 517) ≡ 995 × 309 (mod 517) ≡ 357 (mod 517)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 698 × 95 × 517 = 34282270
  2. We calculate the numbers M1 to M3
    M1=M/m1=34282270/698=49115,   M2=M/m2=34282270/95=360866,   M3=M/m3=34282270/517=66310
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    698491150698010
    4911569870255101
    698255218801-2
    2551881671-23
    18867254-23-8
    67541133-811
    541342-811-52
    1326111-52323
    2120-52323-698
    So our multiplicative inverse is 323 mod 698 ≡ 323
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    95360866095010
    36086695379856101
    955613901-1
    56391171-12
    391725-12-5
    175322-517
    5221-517-39
    212017-3995
    So our multiplicative inverse is -39 mod 95 ≡ 56
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    517663100517010
    66310517128134101
    517134311501-3
    1341151191-34
    1151961-34-27
    1911904-27517
    So our multiplicative inverse is -27 mod 517 ≡ 490
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (587 × 49115 × 323 +
       39 × 360866 × 56 +
       357 × 66310 × 490)   mod 34282270
    = 33598119 (mod 34282270)


    So our answer is 33598119 (mod 34282270).


Verification

So we found that x ≡ 33598119
If this is correct, then the following statements (i.e. the original equations) are true:
551x (mod 698) ≡ 961 (mod 698)
49x (mod 95) ≡ 391 (mod 95)
947x (mod 517) ≡ 995 (mod 517)

Let's see whether that's indeed the case if we use x ≡ 33598119.