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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
3539810353010
9813532275101
35327517801-1
275783411-14
7841137-14-5
4137144-59
37491-59-86
41409-86353
So our multiplicative inverse is -86 mod 353 ≡ 267
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
4217960421010
7964211375101
42137514601-1
37546871-19
46764-19-55
74139-5564
4311-5564-119
313064-119421
So our multiplicative inverse is -119 mod 421 ≡ 302
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
3735470373010
5473731174101
37317422501-2
174256241-213
252411-213-15
24124013-15373
So our multiplicative inverse is -15 mod 373 ≡ 358
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 140 × 981-1 (mod 353) ≡ 140 × 267 (mod 353) ≡ 315 (mod 353)
x ≡ 848 × 796-1 (mod 421) ≡ 848 × 302 (mod 421) ≡ 128 (mod 421)
x ≡ 297 × 547-1 (mod 373) ≡ 297 × 358 (mod 373) ≡ 21 (mod 373)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 353 × 421 × 373 = 55432649
  2. We calculate the numbers M1 to M3
    M1=M/m1=55432649/353=157033,   M2=M/m2=55432649/421=131669,   M3=M/m3=55432649/373=148613
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    3531570330353010
    157033353444301101
    35330115201-1
    301525411-16
    5241111-16-7
    4111386-727
    11813-727-34
    832227-3495
    3211-3495-129
    212095-129353
    So our multiplicative inverse is -129 mod 353 ≡ 224
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    4211316690421010
    131669421312317101
    421317110401-1
    317104351-14
    1045204-14-81
    54114-8185
    4140-8185-421
    So our multiplicative inverse is 85 mod 421 ≡ 85
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    3731486130373010
    148613373398159101
    37315925501-2
    159552491-25
    554916-25-7
    496815-761
    6160-761-373
    So our multiplicative inverse is 61 mod 373 ≡ 61
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (315 × 157033 × 224 +
       128 × 131669 × 85 +
       21 × 148613 × 61)   mod 55432649
    = 9103832 (mod 55432649)


    So our answer is 9103832 (mod 55432649).


Verification

So we found that x ≡ 9103832
If this is correct, then the following statements (i.e. the original equations) are true:
981x (mod 353) ≡ 140 (mod 353)
796x (mod 421) ≡ 848 (mod 421)
547x (mod 373) ≡ 297 (mod 373)

Let's see whether that's indeed the case if we use x ≡ 9103832.