Bootstrap
  C.R.T. .com
It doesn't have to be difficult if someone just explains it right.

Welcome to ChineseRemainderTheorem.com!

×

Modal Header

Some text in the Modal Body

Some other text...

Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
98346625101-2
46651971-219
51772-219-135
723119-135424
2120-135424-983
So our multiplicative inverse is 424 mod 983 ≡ 424
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
467319114801-1
3191482231-13
14823610-13-19
2310233-1941
10331-1941-142
313041-142467
So our multiplicative inverse is -142 mod 467 ≡ 325
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
391232115901-1
2321591731-12
15973213-12-5
7313582-527
13815-527-32
851327-3259
5312-3259-91
321159-91150
2120-91150-391
So our multiplicative inverse is 150 mod 391 ≡ 150
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 889 × 466-1 (mod 983) ≡ 889 × 424 (mod 983) ≡ 447 (mod 983)
x ≡ 78 × 319-1 (mod 467) ≡ 78 × 325 (mod 467) ≡ 132 (mod 467)
x ≡ 952 × 232-1 (mod 391) ≡ 952 × 150 (mod 391) ≡ 85 (mod 391)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 983 × 467 × 391 = 179492851
  2. We calculate the numbers M1 to M3
    M1=M/m1=179492851/983=182597,   M2=M/m2=179492851/467=384353,   M3=M/m3=179492851/391=459061
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    9831825970983010
    182597983185742101
    983742124101-1
    7422413191-14
    241191213-14-49
    1913164-4953
    13621-4953-155
    616053-155983
    So our multiplicative inverse is -155 mod 983 ≡ 828
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    4673843530467010
    38435346782312101
    46712381101-38
    1211111-3839
    111110-3839-467
    So our multiplicative inverse is 39 mod 467 ≡ 39
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    3914590610391010
    459061391117427101
    39127141301-14
    2713211-1429
    131130-1429-391
    So our multiplicative inverse is 29 mod 391 ≡ 29
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (447 × 182597 × 828 +
       132 × 384353 × 39 +
       85 × 459061 × 29)   mod 179492851
    = 151615418 (mod 179492851)


    So our answer is 151615418 (mod 179492851).


Verification

So we found that x ≡ 151615418
If this is correct, then the following statements (i.e. the original equations) are true:
466x (mod 983) ≡ 889 (mod 983)
319x (mod 467) ≡ 78 (mod 467)
232x (mod 391) ≡ 952 (mod 391)

Let's see whether that's indeed the case if we use x ≡ 151615418.