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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
823559126401-1
5592642311-13
26431816-13-25
31161153-2528
161511-2528-53
15115028-53823
So our multiplicative inverse is -53 mod 823 ≡ 770
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
85316453301-5
164334321-521
333211-521-26
32132021-26853
So our multiplicative inverse is -26 mod 853 ≡ 827
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
7817820781010
78278111101
7811781001-781
So our multiplicative inverse is 1 mod 781 ≡ 1
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 807 × 559-1 (mod 823) ≡ 807 × 770 (mod 823) ≡ 25 (mod 823)
x ≡ 28 × 164-1 (mod 853) ≡ 28 × 827 (mod 853) ≡ 125 (mod 853)
x ≡ 371 × 782-1 (mod 781) ≡ 371 × 1 (mod 781) ≡ 371 (mod 781)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 823 × 853 × 781 = 548276839
  2. We calculate the numbers M1 to M3
    M1=M/m1=548276839/823=666193,   M2=M/m2=548276839/853=642763,   M3=M/m3=548276839/781=702019
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    8236661930823010
    666193823809386101
    82338625101-2
    386517291-215
    5129122-215-17
    29221715-1732
    22731-1732-113
    717032-113823
    So our multiplicative inverse is -113 mod 823 ≡ 710
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    8536427630853010
    642763853753454101
    853454139901-1
    4543991551-12
    39955714-12-15
    55143132-1547
    141311-1547-62
    13113047-62853
    So our multiplicative inverse is -62 mod 853 ≡ 791
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    7817020190781010
    702019781898681101
    781681110001-1
    6811006811-17
    10081119-17-8
    8119457-839
    19534-839-125
    541139-125164
    4140-125164-781
    So our multiplicative inverse is 164 mod 781 ≡ 164
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (25 × 666193 × 710 +
       125 × 642763 × 791 +
       371 × 702019 × 164)   mod 548276839
    = 212241026 (mod 548276839)


    So our answer is 212241026 (mod 548276839).


Verification

So we found that x ≡ 212241026
If this is correct, then the following statements (i.e. the original equations) are true:
559x (mod 823) ≡ 807 (mod 823)
164x (mod 853) ≡ 28 (mod 853)
782x (mod 781) ≡ 371 (mod 781)

Let's see whether that's indeed the case if we use x ≡ 212241026.