Welcome to ChineseRemainderTheorem.com!
Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .
This removes all numbers from the textboxes, such that you can fill in your own.
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This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.
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Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!
Want to know more?- Read about how to execute the Chinese Remainder Theorem
- Discover different ways to calculate multiplicative inverses
Transform the equations
You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.
First, we calculate the inverses of the leftmost value on each row:
| n | b | q | r | t1 | t2 | t3 |
|---|---|---|---|---|---|---|
| 467 | 41 | 11 | 16 | 0 | 1 | -11 |
| 41 | 16 | 2 | 9 | 1 | -11 | 23 |
| 16 | 9 | 1 | 7 | -11 | 23 | -34 |
| 9 | 7 | 1 | 2 | 23 | -34 | 57 |
| 7 | 2 | 3 | 1 | -34 | 57 | -205 |
| 2 | 1 | 2 | 0 | 57 | -205 | 467 |
Source: ExtendedEuclideanAlgorithm.com
| n | b | q | r | t1 | t2 | t3 |
|---|---|---|---|---|---|---|
| 107 | 888 | 0 | 107 | 0 | 1 | 0 |
| 888 | 107 | 8 | 32 | 1 | 0 | 1 |
| 107 | 32 | 3 | 11 | 0 | 1 | -3 |
| 32 | 11 | 2 | 10 | 1 | -3 | 7 |
| 11 | 10 | 1 | 1 | -3 | 7 | -10 |
| 10 | 1 | 10 | 0 | 7 | -10 | 107 |
Source: ExtendedEuclideanAlgorithm.com
| n | b | q | r | t1 | t2 | t3 |
|---|---|---|---|---|---|---|
| 641 | 242 | 2 | 157 | 0 | 1 | -2 |
| 242 | 157 | 1 | 85 | 1 | -2 | 3 |
| 157 | 85 | 1 | 72 | -2 | 3 | -5 |
| 85 | 72 | 1 | 13 | 3 | -5 | 8 |
| 72 | 13 | 5 | 7 | -5 | 8 | -45 |
| 13 | 7 | 1 | 6 | 8 | -45 | 53 |
| 7 | 6 | 1 | 1 | -45 | 53 | -98 |
| 6 | 1 | 6 | 0 | 53 | -98 | 641 |
Source: ExtendedEuclideanAlgorithm.com
Click on any row to reveal a more detailed calculation of each multiplicative inverse.
Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:
x ≡ 500 × 41-1 (mod 467) ≡ 500 × 262 (mod 467) ≡ 240 (mod 467)x ≡ 123 × 888-1 (mod 107) ≡ 123 × 97 (mod 107) ≡ 54 (mod 107)x ≡ 901 × 242-1 (mod 641) ≡ 901 × 543 (mod 641) ≡ 160 (mod 641)
So now we have the following equations of the form x ≡ a (mod m):
x ≡ 240 (mod 467)
x ≡ 54 (mod 107)
x ≡ 160 (mod 641)
Now the actual calculation
- Find the common modulus M
M = m1 × m2 × ... × mk = 467 × 107 × 641 = 32030129 - We calculate the numbers M1 to M3
M1=M/m1=32030129/467=68587,M2=M/m2=32030129/107=299347,M3=M/m3=32030129/641=49969 - We now calculate the modular multiplicative inverses M1-1 to M3-1
Have a look at the page that explains how to calculate modular multiplicative inverse.
Using, for example, the Extended Euclidean Algorithm, we will find that:
So our multiplicative inverse is -113 mod 467 ≡ 354n b q r t1 t2 t3 467 68587 0 467 0 1 0 68587 467 146 405 1 0 1 467 405 1 62 0 1 -1 405 62 6 33 1 -1 7 62 33 1 29 -1 7 -8 33 29 1 4 7 -8 15 29 4 7 1 -8 15 -113 4 1 4 0 15 -113 467
Source: ExtendedEuclideanAlgorithm.com
So our multiplicative inverse is -11 mod 107 ≡ 96n b q r t1 t2 t3 107 299347 0 107 0 1 0 299347 107 2797 68 1 0 1 107 68 1 39 0 1 -1 68 39 1 29 1 -1 2 39 29 1 10 -1 2 -3 29 10 2 9 2 -3 8 10 9 1 1 -3 8 -11 9 1 9 0 8 -11 107
Source: ExtendedEuclideanAlgorithm.com
So our multiplicative inverse is 221 mod 641 ≡ 221n b q r t1 t2 t3 641 49969 0 641 0 1 0 49969 641 77 612 1 0 1 641 612 1 29 0 1 -1 612 29 21 3 1 -1 22 29 3 9 2 -1 22 -199 3 2 1 1 22 -199 221 2 1 2 0 -199 221 -641
Source: ExtendedEuclideanAlgorithm.com
- Now we can calculate x with the equation we saw earlier
x = (a1 × M1 × M1-1 + a2 × M2 × M2-1 + ... + ak × Mk × Mk-1) mod M
= (240 × 68587 × 354 +
54 × 299347 × 96 +
160 × 49969 × 221) mod 32030129
= 17283443 (mod 32030129)
So our answer is 17283443 (mod 32030129).
Verification
So we found that x ≡ 17283443
If this is correct, then the following statements (i.e. the original equations) are true:
41x (mod 467) ≡ 500 (mod 467)
888x (mod 107) ≡ 123 (mod 107)
242x (mod 641) ≡ 901 (mod 641)
Let's see whether that's indeed the case if we use x ≡ 17283443.