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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
809460134901-1
46034911111-12
349111316-12-7
111166152-744
161511-744-51
15115044-51809
So our multiplicative inverse is -51 mod 809 ≡ 758
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
43318226901-2
182692441-25
6944125-25-7
44251195-712
251916-712-19
1963112-1969
6160-1969-433
So our multiplicative inverse is 69 mod 433 ≡ 69
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
1872660187010
266187179101
1877922901-2
79292211-25
292118-25-7
218255-719
8513-719-26
531219-2645
3211-2645-71
212045-71187
So our multiplicative inverse is -71 mod 187 ≡ 116
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 513 × 460-1 (mod 809) ≡ 513 × 758 (mod 809) ≡ 534 (mod 809)
x ≡ 168 × 182-1 (mod 433) ≡ 168 × 69 (mod 433) ≡ 334 (mod 433)
x ≡ 261 × 266-1 (mod 187) ≡ 261 × 116 (mod 187) ≡ 169 (mod 187)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 809 × 433 × 187 = 65505539
  2. We calculate the numbers M1 to M3
    M1=M/m1=65505539/809=80971,   M2=M/m2=65505539/433=151283,   M3=M/m3=65505539/187=350297
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    809809710809010
    8097180910071101
    80971112801-11
    71282151-1123
    2815113-1123-34
    15131223-3457
    13261-3457-376
    212057-376809
    So our multiplicative inverse is -376 mod 809 ≡ 433
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    4331512830433010
    151283433349166101
    433166210101-2
    1661011651-23
    10165136-23-5
    65361293-58
    362917-58-13
    297418-1360
    7170-1360-433
    So our multiplicative inverse is 60 mod 433 ≡ 60
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    1873502970187010
    350297187187346101
    187464301-4
    4631511-461
    3130-461-187
    So our multiplicative inverse is 61 mod 187 ≡ 61
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (534 × 80971 × 433 +
       334 × 151283 × 60 +
       169 × 350297 × 61)   mod 65505539
    = 14556062 (mod 65505539)


    So our answer is 14556062 (mod 65505539).


Verification

So we found that x ≡ 14556062
If this is correct, then the following statements (i.e. the original equations) are true:
460x (mod 809) ≡ 513 (mod 809)
182x (mod 433) ≡ 168 (mod 433)
266x (mod 187) ≡ 261 (mod 187)

Let's see whether that's indeed the case if we use x ≡ 14556062.