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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
9479411601-1
941615651-1157
6511-1157-158
5150157-158947
So our multiplicative inverse is -158 mod 947 ≡ 789
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
817330215701-2
3301572161-25
15716913-25-47
1613135-4752
13341-4752-255
313052-255817
So our multiplicative inverse is -255 mod 817 ≡ 562
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
833582125101-1
5822512801-13
25180311-13-10
8011733-1073
11332-1073-229
321173-229302
2120-229302-833
So our multiplicative inverse is 302 mod 833 ≡ 302
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 254 × 941-1 (mod 947) ≡ 254 × 789 (mod 947) ≡ 589 (mod 947)
x ≡ 381 × 330-1 (mod 817) ≡ 381 × 562 (mod 817) ≡ 68 (mod 817)
x ≡ 185 × 582-1 (mod 833) ≡ 185 × 302 (mod 833) ≡ 59 (mod 833)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 947 × 817 × 833 = 644491267
  2. We calculate the numbers M1 to M3
    M1=M/m1=644491267/947=680561,   M2=M/m2=644491267/817=788851,   M3=M/m3=644491267/833=773699
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    9476805610947010
    680561947718615101
    947615133201-1
    61533212831-12
    332283149-12-3
    283495382-317
    4938111-317-20
    38113517-2077
    11521-2077-174
    515077-174947
    So our multiplicative inverse is -174 mod 947 ≡ 773
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    8177888510817010
    788851817965446101
    817446137101-1
    4463711751-12
    37175471-12-9
    7571142-911
    714173-911-196
    431111-196207
    3130-196207-817
    So our multiplicative inverse is 207 mod 817 ≡ 207
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    8337736990833010
    773699833928675101
    833675115801-1
    6751584431-15
    15843329-15-16
    43291145-1621
    291421-1621-58
    14114021-58833
    So our multiplicative inverse is -58 mod 833 ≡ 775
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (589 × 680561 × 773 +
       68 × 788851 × 207 +
       59 × 773699 × 775)   mod 644491267
    = 579455684 (mod 644491267)


    So our answer is 579455684 (mod 644491267).


Verification

So we found that x ≡ 579455684
If this is correct, then the following statements (i.e. the original equations) are true:
941x (mod 947) ≡ 254 (mod 947)
330x (mod 817) ≡ 381 (mod 817)
582x (mod 833) ≡ 185 (mod 833)

Let's see whether that's indeed the case if we use x ≡ 579455684.