Welcome to ChineseRemainderTheorem.com!
Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .
This removes all numbers from the textboxes, such that you can fill in your own.
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This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.
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Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!
Want to know more?- Read about how to execute the Chinese Remainder Theorem
- Discover different ways to calculate multiplicative inverses
Transform the equations
You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.
First, we calculate the inverses of the leftmost value on each row:
| n | b | q | r | t1 | t2 | t3 |
|---|---|---|---|---|---|---|
| 869 | 273 | 3 | 50 | 0 | 1 | -3 |
| 273 | 50 | 5 | 23 | 1 | -3 | 16 |
| 50 | 23 | 2 | 4 | -3 | 16 | -35 |
| 23 | 4 | 5 | 3 | 16 | -35 | 191 |
| 4 | 3 | 1 | 1 | -35 | 191 | -226 |
| 3 | 1 | 3 | 0 | 191 | -226 | 869 |
Source: ExtendedEuclideanAlgorithm.com
| n | b | q | r | t1 | t2 | t3 |
|---|---|---|---|---|---|---|
| 311 | 306 | 1 | 5 | 0 | 1 | -1 |
| 306 | 5 | 61 | 1 | 1 | -1 | 62 |
| 5 | 1 | 5 | 0 | -1 | 62 | -311 |
Source: ExtendedEuclideanAlgorithm.com
| n | b | q | r | t1 | t2 | t3 |
|---|---|---|---|---|---|---|
| 521 | 140 | 3 | 101 | 0 | 1 | -3 |
| 140 | 101 | 1 | 39 | 1 | -3 | 4 |
| 101 | 39 | 2 | 23 | -3 | 4 | -11 |
| 39 | 23 | 1 | 16 | 4 | -11 | 15 |
| 23 | 16 | 1 | 7 | -11 | 15 | -26 |
| 16 | 7 | 2 | 2 | 15 | -26 | 67 |
| 7 | 2 | 3 | 1 | -26 | 67 | -227 |
| 2 | 1 | 2 | 0 | 67 | -227 | 521 |
Source: ExtendedEuclideanAlgorithm.com
Click on any row to reveal a more detailed calculation of each multiplicative inverse.
Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:
x ≡ 803 × 273-1 (mod 869) ≡ 803 × 643 (mod 869) ≡ 143 (mod 869)x ≡ 126 × 306-1 (mod 311) ≡ 126 × 62 (mod 311) ≡ 37 (mod 311)x ≡ 17 × 140-1 (mod 521) ≡ 17 × 294 (mod 521) ≡ 309 (mod 521)
So now we have the following equations of the form x ≡ a (mod m):
x ≡ 143 (mod 869)
x ≡ 37 (mod 311)
x ≡ 309 (mod 521)
Now the actual calculation
- Find the common modulus M
M = m1 × m2 × ... × mk = 869 × 311 × 521 = 140804939 - We calculate the numbers M1 to M3
M1=M/m1=140804939/869=162031,M2=M/m2=140804939/311=452749,M3=M/m3=140804939/521=270259 - We now calculate the modular multiplicative inverses M1-1 to M3-1
Have a look at the page that explains how to calculate modular multiplicative inverse.
Using, for example, the Extended Euclidean Algorithm, we will find that:
So our multiplicative inverse is -197 mod 869 ≡ 672n b q r t1 t2 t3 869 162031 0 869 0 1 0 162031 869 186 397 1 0 1 869 397 2 75 0 1 -2 397 75 5 22 1 -2 11 75 22 3 9 -2 11 -35 22 9 2 4 11 -35 81 9 4 2 1 -35 81 -197 4 1 4 0 81 -197 869
Source: ExtendedEuclideanAlgorithm.com
So our multiplicative inverse is -65 mod 311 ≡ 246n b q r t1 t2 t3 311 452749 0 311 0 1 0 452749 311 1455 244 1 0 1 311 244 1 67 0 1 -1 244 67 3 43 1 -1 4 67 43 1 24 -1 4 -5 43 24 1 19 4 -5 9 24 19 1 5 -5 9 -14 19 5 3 4 9 -14 51 5 4 1 1 -14 51 -65 4 1 4 0 51 -65 311
Source: ExtendedEuclideanAlgorithm.com
So our multiplicative inverse is 227 mod 521 ≡ 227n b q r t1 t2 t3 521 270259 0 521 0 1 0 270259 521 518 381 1 0 1 521 381 1 140 0 1 -1 381 140 2 101 1 -1 3 140 101 1 39 -1 3 -4 101 39 2 23 3 -4 11 39 23 1 16 -4 11 -15 23 16 1 7 11 -15 26 16 7 2 2 -15 26 -67 7 2 3 1 26 -67 227 2 1 2 0 -67 227 -521
Source: ExtendedEuclideanAlgorithm.com
- Now we can calculate x with the equation we saw earlier
x = (a1 × M1 × M1-1 + a2 × M2 × M2-1 + ... + ak × Mk × Mk-1) mod M
= (143 × 162031 × 672 +
37 × 452749 × 246 +
309 × 270259 × 227) mod 140804939
= 67676125 (mod 140804939)
So our answer is 67676125 (mod 140804939).
Verification
So we found that x ≡ 67676125
If this is correct, then the following statements (i.e. the original equations) are true:
273x (mod 869) ≡ 803 (mod 869)
306x (mod 311) ≡ 126 (mod 311)
140x (mod 521) ≡ 17 (mod 521)
Let's see whether that's indeed the case if we use x ≡ 67676125.