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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
419145212901-2
1451291161-23
1291681-23-26
1611603-26419
So our multiplicative inverse is -26 mod 419 ≡ 393
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
4998650499010
8654991366101
499366113301-1
36613321001-13
133100133-13-4
10033313-415
331330-415-499
So our multiplicative inverse is 15 mod 499 ≡ 15
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
62355916401-1
559648471-19
6447117-19-10
47172139-1029
171314-1029-39
1343129-39146
4140-39146-623
So our multiplicative inverse is 146 mod 623 ≡ 146
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 253 × 145-1 (mod 419) ≡ 253 × 393 (mod 419) ≡ 126 (mod 419)
x ≡ 665 × 865-1 (mod 499) ≡ 665 × 15 (mod 499) ≡ 494 (mod 499)
x ≡ 109 × 559-1 (mod 623) ≡ 109 × 146 (mod 623) ≡ 339 (mod 623)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 419 × 499 × 623 = 130257463
  2. We calculate the numbers M1 to M3
    M1=M/m1=130257463/419=310877,   M2=M/m2=130257463/499=261037,   M3=M/m3=130257463/623=209081
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    4193108770419010
    310877419741398101
    41939812101-1
    3982118201-119
    212011-119-20
    20120019-20419
    So our multiplicative inverse is -20 mod 419 ≡ 399
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    4992610370499010
    26103749952360101
    4996081901-8
    6019331-825
    19361-825-158
    313025-158499
    So our multiplicative inverse is -158 mod 499 ≡ 341
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    6232090810623010
    209081623335376101
    623376124701-1
    37624711291-12
    2471291118-12-3
    1291181112-35
    11811108-35-53
    118135-5358
    8322-5358-169
    321158-169227
    2120-169227-623
    So our multiplicative inverse is 227 mod 623 ≡ 227
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (126 × 310877 × 399 +
       494 × 261037 × 341 +
       339 × 209081 × 227)   mod 130257463
    = 11581286 (mod 130257463)


    So our answer is 11581286 (mod 130257463).


Verification

So we found that x ≡ 11581286
If this is correct, then the following statements (i.e. the original equations) are true:
145x (mod 419) ≡ 253 (mod 419)
865x (mod 499) ≡ 665 (mod 499)
559x (mod 623) ≡ 109 (mod 623)

Let's see whether that's indeed the case if we use x ≡ 11581286.