Welcome to ChineseRemainderTheorem.com!
Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .
This removes all numbers from the textboxes, such that you can fill in your own.
This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.
This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.
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Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!
Want to know more?- Read about how to execute the Chinese Remainder Theorem
- Discover different ways to calculate multiplicative inverses
Transform the equations
You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.
First, we calculate the inverses of the leftmost value on each row:
| n | b | q | r | t1 | t2 | t3 |
|---|---|---|---|---|---|---|
| 913 | 810 | 1 | 103 | 0 | 1 | -1 |
| 810 | 103 | 7 | 89 | 1 | -1 | 8 |
| 103 | 89 | 1 | 14 | -1 | 8 | -9 |
| 89 | 14 | 6 | 5 | 8 | -9 | 62 |
| 14 | 5 | 2 | 4 | -9 | 62 | -133 |
| 5 | 4 | 1 | 1 | 62 | -133 | 195 |
| 4 | 1 | 4 | 0 | -133 | 195 | -913 |
Source: ExtendedEuclideanAlgorithm.com
| n | b | q | r | t1 | t2 | t3 |
|---|---|---|---|---|---|---|
| 797 | 812 | 0 | 797 | 0 | 1 | 0 |
| 812 | 797 | 1 | 15 | 1 | 0 | 1 |
| 797 | 15 | 53 | 2 | 0 | 1 | -53 |
| 15 | 2 | 7 | 1 | 1 | -53 | 372 |
| 2 | 1 | 2 | 0 | -53 | 372 | -797 |
Source: ExtendedEuclideanAlgorithm.com
| n | b | q | r | t1 | t2 | t3 |
|---|---|---|---|---|---|---|
| 107 | 897 | 0 | 107 | 0 | 1 | 0 |
| 897 | 107 | 8 | 41 | 1 | 0 | 1 |
| 107 | 41 | 2 | 25 | 0 | 1 | -2 |
| 41 | 25 | 1 | 16 | 1 | -2 | 3 |
| 25 | 16 | 1 | 9 | -2 | 3 | -5 |
| 16 | 9 | 1 | 7 | 3 | -5 | 8 |
| 9 | 7 | 1 | 2 | -5 | 8 | -13 |
| 7 | 2 | 3 | 1 | 8 | -13 | 47 |
| 2 | 1 | 2 | 0 | -13 | 47 | -107 |
Source: ExtendedEuclideanAlgorithm.com
Click on any row to reveal a more detailed calculation of each multiplicative inverse.
Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:
x ≡ 638 × 810-1 (mod 913) ≡ 638 × 195 (mod 913) ≡ 242 (mod 913)x ≡ 239 × 812-1 (mod 797) ≡ 239 × 372 (mod 797) ≡ 441 (mod 797)x ≡ 663 × 897-1 (mod 107) ≡ 663 × 47 (mod 107) ≡ 24 (mod 107)
So now we have the following equations of the form x ≡ a (mod m):
x ≡ 242 (mod 913)
x ≡ 441 (mod 797)
x ≡ 24 (mod 107)
Now the actual calculation
- Find the common modulus M
M = m1 × m2 × ... × mk = 913 × 797 × 107 = 77859727 - We calculate the numbers M1 to M3
M1=M/m1=77859727/913=85279,M2=M/m2=77859727/797=97691,M3=M/m3=77859727/107=727661 - We now calculate the modular multiplicative inverses M1-1 to M3-1
Have a look at the page that explains how to calculate modular multiplicative inverse.
Using, for example, the Extended Euclidean Algorithm, we will find that:
So our multiplicative inverse is -190 mod 913 ≡ 723n b q r t1 t2 t3 913 85279 0 913 0 1 0 85279 913 93 370 1 0 1 913 370 2 173 0 1 -2 370 173 2 24 1 -2 5 173 24 7 5 -2 5 -37 24 5 4 4 5 -37 153 5 4 1 1 -37 153 -190 4 1 4 0 153 -190 913
Source: ExtendedEuclideanAlgorithm.com
So our multiplicative inverse is 218 mod 797 ≡ 218n b q r t1 t2 t3 797 97691 0 797 0 1 0 97691 797 122 457 1 0 1 797 457 1 340 0 1 -1 457 340 1 117 1 -1 2 340 117 2 106 -1 2 -5 117 106 1 11 2 -5 7 106 11 9 7 -5 7 -68 11 7 1 4 7 -68 75 7 4 1 3 -68 75 -143 4 3 1 1 75 -143 218 3 1 3 0 -143 218 -797
Source: ExtendedEuclideanAlgorithm.com
So our multiplicative inverse is -7 mod 107 ≡ 100n b q r t1 t2 t3 107 727661 0 107 0 1 0 727661 107 6800 61 1 0 1 107 61 1 46 0 1 -1 61 46 1 15 1 -1 2 46 15 3 1 -1 2 -7 15 1 15 0 2 -7 107
Source: ExtendedEuclideanAlgorithm.com
- Now we can calculate x with the equation we saw earlier
x = (a1 × M1 × M1-1 + a2 × M2 × M2-1 + ... + ak × Mk × Mk-1) mod M
= (242 × 85279 × 723 +
441 × 97691 × 218 +
24 × 727661 × 100) mod 77859727
= 53980454 (mod 77859727)
So our answer is 53980454 (mod 77859727).
Verification
So we found that x ≡ 53980454
If this is correct, then the following statements (i.e. the original equations) are true:
810x (mod 913) ≡ 638 (mod 913)
812x (mod 797) ≡ 239 (mod 797)
897x (mod 107) ≡ 663 (mod 107)
Let's see whether that's indeed the case if we use x ≡ 53980454.