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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
964799116501-1
79916541391-15
165139126-15-6
13926595-635
26928-635-76
981135-76111
8180-76111-964
So our multiplicative inverse is 111 mod 964 ≡ 111
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
793531126201-1
531262271-13
2627373-13-112
73213-112227
3130-112227-793
So our multiplicative inverse is 227 mod 793 ≡ 227
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
6197010619010
701619182101
6198274501-7
82451371-78
453718-78-15
378458-1568
8513-1568-83
531268-83151
3211-83151-234
2120151-234619
So our multiplicative inverse is -234 mod 619 ≡ 385
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 916 × 799-1 (mod 964) ≡ 916 × 111 (mod 964) ≡ 456 (mod 964)
x ≡ 883 × 531-1 (mod 793) ≡ 883 × 227 (mod 793) ≡ 605 (mod 793)
x ≡ 704 × 701-1 (mod 619) ≡ 704 × 385 (mod 619) ≡ 537 (mod 619)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 964 × 793 × 619 = 473195788
  2. We calculate the numbers M1 to M3
    M1=M/m1=473195788/964=490867,   M2=M/m2=473195788/793=596716,   M3=M/m3=473195788/619=764452
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    9644908670964010
    490867964509191101
    9641915901-5
    19192121-5106
    9241-5106-429
    2120106-429964
    So our multiplicative inverse is -429 mod 964 ≡ 535
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    7935967160793010
    596716793752380101
    79338023301-2
    3803311171-223
    3317116-223-25
    17161123-2548
    161160-2548-793
    So our multiplicative inverse is 48 mod 793 ≡ 48
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    6197644520619010
    7644526191234606101
    61960611301-1
    606134681-147
    13815-147-48
    851347-4895
    5312-4895-143
    321195-143238
    2120-143238-619
    So our multiplicative inverse is 238 mod 619 ≡ 238
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (456 × 490867 × 535 +
       605 × 596716 × 48 +
       537 × 764452 × 238)   mod 473195788
    = 76987424 (mod 473195788)


    So our answer is 76987424 (mod 473195788).


Verification

So we found that x ≡ 76987424
If this is correct, then the following statements (i.e. the original equations) are true:
799x (mod 964) ≡ 916 (mod 964)
531x (mod 793) ≡ 883 (mod 793)
701x (mod 619) ≡ 704 (mod 619)

Let's see whether that's indeed the case if we use x ≡ 76987424.