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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
2272390227010
239227112101
22712181101-18
1211111-1819
111110-1819-227
So our multiplicative inverse is 19 mod 227 ≡ 19
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
951599135201-1
59935212471-12
3522471105-12-3
2471052372-38
10537231-38-19
3731168-1927
31651-1927-154
616027-154951
So our multiplicative inverse is -154 mod 951 ≡ 797
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
90720548701-4
205872311-49
8731225-49-22
3125169-2231
25641-2231-146
616031-146907
So our multiplicative inverse is -146 mod 907 ≡ 761
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 237 × 239-1 (mod 227) ≡ 237 × 19 (mod 227) ≡ 190 (mod 227)
x ≡ 454 × 599-1 (mod 951) ≡ 454 × 797 (mod 951) ≡ 458 (mod 951)
x ≡ 619 × 205-1 (mod 907) ≡ 619 × 761 (mod 907) ≡ 326 (mod 907)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 227 × 951 × 907 = 195800439
  2. We calculate the numbers M1 to M3
    M1=M/m1=195800439/227=862557,   M2=M/m2=195800439/951=205889,   M3=M/m3=195800439/907=215877
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    2278625570227010
    8625572273799184101
    22718414301-1
    184434121-15
    431237-15-16
    127155-1621
    7512-1621-37
    522121-3795
    2120-3795-227
    So our multiplicative inverse is 95 mod 227 ≡ 95
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    9512058890951010
    205889951216473101
    9514732501-2
    47359431-2189
    5312-2189-191
    3211189-191380
    2120-191380-951
    So our multiplicative inverse is 380 mod 951 ≡ 380
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    9072158770907010
    21587790723811101
    9071182501-82
    115211-82165
    5150-82165-907
    So our multiplicative inverse is 165 mod 907 ≡ 165
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (190 × 862557 × 95 +
       458 × 205889 × 380 +
       326 × 215877 × 165)   mod 195800439
    = 162158321 (mod 195800439)


    So our answer is 162158321 (mod 195800439).


Verification

So we found that x ≡ 162158321
If this is correct, then the following statements (i.e. the original equations) are true:
239x (mod 227) ≡ 237 (mod 227)
599x (mod 951) ≡ 454 (mod 951)
205x (mod 907) ≡ 619 (mod 907)

Let's see whether that's indeed the case if we use x ≡ 162158321.