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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
959505145401-1
5054541511-12
45451846-12-17
5146152-1719
46591-1719-188
515019-188959
So our multiplicative inverse is -188 mod 959 ≡ 771
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
948341226601-2
3412661751-23
26675341-23-11
75411343-1114
413417-1114-25
3474614-25114
7611-25114-139
6160114-139948
So our multiplicative inverse is -139 mod 948 ≡ 809
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
755593116201-1
59316231071-14
162107155-14-5
107551524-59
555213-59-14
5231719-14247
3130-14247-755
So our multiplicative inverse is 247 mod 755 ≡ 247
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 893 × 505-1 (mod 959) ≡ 893 × 771 (mod 959) ≡ 900 (mod 959)
x ≡ 835 × 341-1 (mod 948) ≡ 835 × 809 (mod 948) ≡ 539 (mod 948)
x ≡ 715 × 593-1 (mod 755) ≡ 715 × 247 (mod 755) ≡ 690 (mod 755)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 959 × 948 × 755 = 686394660
  2. We calculate the numbers M1 to M3
    M1=M/m1=686394660/959=715740,   M2=M/m2=686394660/948=724045,   M3=M/m3=686394660/755=909132
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    9597157400959010
    715740959746326101
    959326230701-2
    3263071191-23
    30719163-23-50
    193613-50303
    3130-50303-959
    So our multiplicative inverse is 303 mod 959 ≡ 303
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    9487240450948010
    724045948763721101
    948721122701-1
    7212273401-14
    22740527-14-21
    40271134-2125
    271321-2125-71
    13113025-71948
    So our multiplicative inverse is -71 mod 948 ≡ 877
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    7559091320755010
    9091327551204112101
    75511268301-6
    112831291-67
    8329225-67-20
    2925147-2027
    25461-2027-182
    414027-182755
    So our multiplicative inverse is -182 mod 755 ≡ 573
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (900 × 715740 × 303 +
       539 × 724045 × 877 +
       690 × 909132 × 573)   mod 686394660
    = 452634515 (mod 686394660)


    So our answer is 452634515 (mod 686394660).


Verification

So we found that x ≡ 452634515
If this is correct, then the following statements (i.e. the original equations) are true:
505x (mod 959) ≡ 893 (mod 959)
341x (mod 948) ≡ 835 (mod 948)
593x (mod 755) ≡ 715 (mod 755)

Let's see whether that's indeed the case if we use x ≡ 452634515.