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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
3139180313010
9183132292101
31329212101-1
2922113191-114
211912-114-15
1929114-15149
2120-15149-313
So our multiplicative inverse is 149 mod 313 ≡ 149
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
941587135401-1
58735412331-12
3542331121-12-3
23312111122-35
12111219-35-8
11291245-8101
9421-8101-210
4140101-210941
So our multiplicative inverse is -210 mod 941 ≡ 731
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
19317411901-1
17419931-110
19361-110-61
313010-61193
So our multiplicative inverse is -61 mod 193 ≡ 132
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 61 × 918-1 (mod 313) ≡ 61 × 149 (mod 313) ≡ 12 (mod 313)
x ≡ 22 × 587-1 (mod 941) ≡ 22 × 731 (mod 941) ≡ 85 (mod 941)
x ≡ 492 × 174-1 (mod 193) ≡ 492 × 132 (mod 193) ≡ 96 (mod 193)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 313 × 941 × 193 = 56844869
  2. We calculate the numbers M1 to M3
    M1=M/m1=56844869/313=181613,   M2=M/m2=56844869/941=60409,   M3=M/m3=56844869/193=294533
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    3131816130313010
    18161331358073101
    3137342101-4
    73213101-413
    211021-413-30
    10110013-30313
    So our multiplicative inverse is -30 mod 313 ≡ 283
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    941604090941010
    6040994164185101
    94118551601-5
    185161191-556
    16917-556-61
    971256-61117
    7231-61117-412
    2120117-412941
    So our multiplicative inverse is -412 mod 941 ≡ 529
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    1932945330193010
    294533193152615101
    19315121301-12
    1513121-1213
    13261-1213-90
    212013-90193
    So our multiplicative inverse is -90 mod 193 ≡ 103
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (12 × 181613 × 283 +
       85 × 60409 × 529 +
       96 × 294533 × 103)   mod 56844869
    = 49300016 (mod 56844869)


    So our answer is 49300016 (mod 56844869).


Verification

So we found that x ≡ 49300016
If this is correct, then the following statements (i.e. the original equations) are true:
918x (mod 313) ≡ 61 (mod 313)
587x (mod 941) ≡ 22 (mod 941)
174x (mod 193) ≡ 492 (mod 193)

Let's see whether that's indeed the case if we use x ≡ 49300016.