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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

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Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
4439810443010
981443295101
4439546301-4
95631321-45
6332131-45-9
3231115-914
311310-914-443
So our multiplicative inverse is 14 mod 443 ≡ 14
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
764467129701-1
46729711701-12
2971701127-12-3
1701271432-35
12743241-35-13
4341125-1318
412201-1318-373
212018-373764
So our multiplicative inverse is -373 mod 764 ≡ 391
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
953673128001-1
67328021131-13
280113254-13-7
11354253-717
545104-717-177
541117-177194
4140-177194-953
So our multiplicative inverse is 194 mod 953 ≡ 194
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 824 × 981-1 (mod 443) ≡ 824 × 14 (mod 443) ≡ 18 (mod 443)
x ≡ 60 × 467-1 (mod 764) ≡ 60 × 391 (mod 764) ≡ 540 (mod 764)
x ≡ 264 × 673-1 (mod 953) ≡ 264 × 194 (mod 953) ≡ 707 (mod 953)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 443 × 764 × 953 = 322544756
  2. We calculate the numbers M1 to M3
    M1=M/m1=322544756/443=728092,   M2=M/m2=322544756/764=422179,   M3=M/m3=322544756/953=338452
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    4437280920443010
    7280924431643243101
    443243120001-1
    2432001431-12
    20043428-12-9
    43281152-911
    2815113-911-20
    15131211-2031
    13261-2031-206
    212031-206443
    So our multiplicative inverse is -206 mod 443 ≡ 237
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    7644221790764010
    422179764552451101
    764451131301-1
    45131311381-12
    313138237-12-5
    138373272-517
    3727110-517-22
    27102717-2261
    10713-2261-83
    732161-83227
    3130-83227-764
    So our multiplicative inverse is 227 mod 764 ≡ 227
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    9533384520953010
    338452953355137101
    953137613101-6
    137131161-67
    1316215-67-153
    65117-153160
    5150-153160-953
    So our multiplicative inverse is 160 mod 953 ≡ 160
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (18 × 728092 × 237 +
       540 × 422179 × 227 +
       707 × 338452 × 160)   mod 322544756
    = 249542804 (mod 322544756)


    So our answer is 249542804 (mod 322544756).


Verification

So we found that x ≡ 249542804
If this is correct, then the following statements (i.e. the original equations) are true:
981x (mod 443) ≡ 824 (mod 443)
467x (mod 764) ≡ 60 (mod 764)
673x (mod 953) ≡ 264 (mod 953)

Let's see whether that's indeed the case if we use x ≡ 249542804.