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Welcome to ChineseRemainderTheorem.com!

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Use the calculator below to get a step-by-step calculation of the Chinese Remainder Theory. Just enter the numbers you would like and press "Calculate" .


This removes all numbers from the textboxes, such that you can fill in your own.

This fills all textboxes with random numbers. If you fill in random numbers yourself, it is very likely that those numbers do not have a solution. To avoid disappointment, use this button instead! It only uses random numbers that do have a solution.

This button is similar to the "Clear everything" button, but only clears the left column.
This is useful if you want your equations to be of the form x ≡ a (mod m) rather than bx ≡ a (mod m).
In that case, it can be especially useful after using the random numbers button.

Do you want to use more equations? Go ahead and use this button. It adds another row that you can fill in. Not sure what numbers to put in this newly added row? Use the random numbers button again!

Do you have too many rows? Use one of these buttons to remove a row. You can always add a row again using the yellow "Add a row" button.

Are you ready to view a full step-by-step Chinese Remainder Theorem calculation for the numbers you have entered? Then use this button!

Want to know more?


Transform the equations

You used one or more of the fields on the left, so your equations are of the form bx ≡ a mod m.
We want them to be of the form x ≡ a mod m, so we need to move the values on the left to the right side of the equation.
For a more detailed explanation about how this works, see this part of our page about how to execute the Chinese Remainder algorithm.

First, we calculate the inverses of the leftmost value on each row:

nbqr t1t2t3
6897450689010
745689156101
68956121701-12
5617351-1237
17532-1237-123
522137-123283
2120-123283-689
So our multiplicative inverse is 283 mod 689 ≡ 283
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
943677126601-1
67726621451-13
2661451121-13-4
1451211243-47
1212451-47-39
2412407-39943
So our multiplicative inverse is -39 mod 943 ≡ 904
Source: ExtendedEuclideanAlgorithm.com

nbqr t1t2t3
6611096701-6
10971541-691
7413-691-97
431191-97188
3130-97188-661
So our multiplicative inverse is 188 mod 661 ≡ 188
Source: ExtendedEuclideanAlgorithm.com

Click on any row to reveal a more detailed calculation of each multiplicative inverse.

Now that we now the inverses, let's move the leftmost value on each row to the right of the equation:

x ≡ 640 × 745-1 (mod 689) ≡ 640 × 283 (mod 689) ≡ 602 (mod 689)
x ≡ 365 × 677-1 (mod 943) ≡ 365 × 904 (mod 943) ≡ 853 (mod 943)
x ≡ 957 × 109-1 (mod 661) ≡ 957 × 188 (mod 661) ≡ 124 (mod 661)


Now the actual calculation

  1. Find the common modulus M
    M = m1 × m2 × ... × mk = 689 × 943 × 661 = 429469547
  2. We calculate the numbers M1 to M3
    M1=M/m1=429469547/689=623323,   M2=M/m2=429469547/943=455429,   M3=M/m3=429469547/661=649727
  3. We now calculate the modular multiplicative inverses M1-1 to M3-1
    Have a look at the page that explains how to calculate modular multiplicative inverse.
    Using, for example, the Extended Euclidean Algorithm, we will find that:

    nbqr t1t2t3
    6896233230689010
    623323689904467101
    689467122201-1
    4672222231-13
    22223915-13-28
    2315183-2831
    15817-2831-59
    871131-5990
    7170-5990-689
    So our multiplicative inverse is 90 mod 689 ≡ 90
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    9434554290943010
    455429943482903101
    94390314001-1
    9034022231-123
    4023117-123-24
    23171623-2447
    17625-2447-118
    651147-118165
    5150-118165-943
    So our multiplicative inverse is 165 mod 943 ≡ 165
    Source: ExtendedEuclideanAlgorithm.com

    nbqr t1t2t3
    6616497270661010
    649727661982625101
    66162513601-1
    6253617131-118
    3613210-118-37
    13101318-3755
    10331-3755-202
    313055-202661
    So our multiplicative inverse is -202 mod 661 ≡ 459
    Source: ExtendedEuclideanAlgorithm.com
  4. Now we can calculate x with the equation we saw earlier
    x = (a1 × M1 × M1-1   +   a2 × M2 × M2-1   + ... +   ak × Mk × Mk-1)   mod M
    =  (602 × 623323 × 90 +
       853 × 455429 × 165 +
       124 × 649727 × 459)   mod 429469547
    = 426888466 (mod 429469547)


    So our answer is 426888466 (mod 429469547).


Verification

So we found that x ≡ 426888466
If this is correct, then the following statements (i.e. the original equations) are true:
745x (mod 689) ≡ 640 (mod 689)
677x (mod 943) ≡ 365 (mod 943)
109x (mod 661) ≡ 957 (mod 661)

Let's see whether that's indeed the case if we use x ≡ 426888466.